1.

A person standing between the two vertical cliffs produces a sound. Two successive echoes are heard at 4 s and 6 s. Calculate the distance between the cliffs.(speed of sound in air = 320 m s-1)

Answer»

The distance of first cliff from the person, 2 × D1 = velocity x time

D1 = 320 × 4 / 2 = 640 m

Distance of the second cliff from the person, D2 = 320 × 6 / 2 = 960 m

Distance between cliffs = D1 + D2 = 640 + 960 = 1600 m



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