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A person's salary increased from Rs. 8,100 to Rs. 9,000. What is the percentage increase in his salary?1. \(6 \frac 1 9 \%\)2. \(11 \frac 1 9 \%\)3. \(9 \frac 1 9 \%\)4. \(13 \frac 7 9 \%\) |
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Answer» Correct Answer - Option 2 : \(11 \frac 1 9 \%\) Given: Initial salary = Rs. 8100 Increased salary = Rs. 9000 Formula used: Percentage increased = (Initial salary – Increased salary)/Initial salary × 100 Calculation: Initial salary = Rs. 8100 Increased salary = Rs. 9000 Percentage increased = (Initial salary – Increased salary)/Initial salary × 100 ⇒ Required percent = (9000 – 8100)/8100 × 100 ⇒ Required percent = 900/8100 × 100 ⇒ Required percent = 1/9 × 100 ⇒ Required percent = 100/9% ⇒ Required percent = \(11\frac{1}{9}\% \) ∴ The percentage increase in his salary is \(11\frac{1}{9}\% \). |
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