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A person P observes that a car is moving with 10 m/s due north and another person Q observes that same car is moving with 10 m/s due south. Whose observations are correct? Comment on situation |
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Answer» Man 'A' moves in NORTH direction with speed 10 m/sSo we can writev a =0 i^ +10 j^ Now for other personMan 'B' moves in 30 North of EAST with 10m/sso we can writev b =10cos30 i^ +10sin30 j^ v b =5 3 i^ +5 j^ Now the relative velocity of B with respect to A is given byv ba = b − a v ba =(5 3 i^ +5 j^ )−(0 i^ +10 j^ )v ba =5 3 i^ −5 j^ Magnitude is given by∣v ba ∣= (5 3 ) 2 +(−5) 2 ∣v ba ∣=10 m/sTherefore the relative velocity of B w.r.t A is 10 m/s |
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