A person of mass 50 kg stands on a weighing scale on a lift. If the li

1.	A person of mass 50 kg stands on a weighing scale on a lift. If the lift is descending with a downward acceleration of 9 m s–2, what would be the reading of the weighing scale? (g = 10 m s–2)
Answer» Let R be the reading of the scale, in newtons. Effective downward acceleration = (50g - R)/50 = g R = 5g = 50N. (The weighing scale will show 5 kg).

A person of mass 50 kg stands on a weighing scale on a lift. If the lift is descending with a downward acceleration of 9 m s–2, what would be the reading of the weighing scale? (g = 10 m s–2)

Answer»

Let R be the reading of the scale, in newtons. Effective downward acceleration = (50g - R)/50 = g

R = 5g = 50N. (The weighing scale will show 5 kg).