A person moves along the boundary of a square field of side 10m in 20 seconds . what will be the magnitude of displacement of that person at the end of 2 minutes 20 seconds?

A person moves along the boundary of a square field of side 10m in 20

1.	A person moves along the boundary of a square field of side 10m in 20 seconds . what will be the magnitude of displacement of that person at the end of 2 minutes 20 seconds?
Answer» DISPLACEMENT =0 , speed =2 m/s and distance =40 mdisplacement is shortest path between final and initial position . The person reach the initial position at last THEREFORE displacement is 0 m.Distance is total length traveled it 40 m as he moved one round against a square having length of one SIDE 10 m.speed is total distance DIVIDED by total time which is 40 divided by 20 m/s.

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A person moves along the boundary of a square field of side 10m in 20 seconds . what will be the magnitude of displacement of that person at the end of 2 minutes 20 seconds? ​

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A person moves along the boundary of a square field of side 10m in 20 seconds . what will be the magnitude of displacement of that person at the end of 2 minutes 20 seconds?