A person is flying a kite at an angle of elevation 60° The length of

1.	A person is flying a kite at an angle of elevation 60° The length of the thread is 30m .find the height of a flying kite from the ground
Answer» Question: A person is flying a KITE at an angle of ELEVATION 60° The length of the thread is 30 m. Find the height of a flying kite from the ground. Answer: The height of the kite flying from the ground is 25.98 m. Given: The angle of elevation is 60°. The length of the thread is 30 m. To find: The height of the kite from the ground. Explanation: Let, ABC is a right ANGLED triangle in which, ∠B=90°, ∠C = 60° and CA = 30 m. Hence we get, Perpendicular = AB Base = BC Hypotenuse = AC=30 m. *We know that,* sin θ = $\frac{perpendicular}{hypotenuse}$ sin 60° = $\frac{\sqrt{3} }{2}$ ∴ $\frac{AB}{AC}= \frac{\sqrt{3} }{2}$ ⇒ $\frac{AB}{30} = \frac{\sqrt{3} }{2}$ ⇒ $\frac{AB}{<klux>15</klux>}=\sqrt{3}$ ⇒ AB = 1.732 × 15 = 25.98 m. ∴ The height of the kite from the ground is 25.98 m. Refer to the attachment for the figure and explanation.

A person is flying a kite at an angle of elevation 60° The length of the thread is 30m .find the height of a flying kite from the ground

Answer»

A person is flying a KITE at an angle of ELEVATION 60° The length of the thread is 30 m. Find the height of a flying kite from the ground.

The angle of elevation is 60°.

The length of the thread is 30 m.

The height of the kite from the ground.

Let, ABC is a right ANGLED triangle in which, ∠B=90°, ∠C = 60° and CA = 30 m.

Hence we get,

Perpendicular = AB

Base = BC

Hypotenuse = AC=30 m.

We know that,

sin θ = $\frac{perpendicular}{hypotenuse}$

sin 60° = $\frac{\sqrt{3} }{2}$

∴ $\frac{AB}{AC}= \frac{\sqrt{3} }{2}$

⇒ $\frac{AB}{30} = \frac{\sqrt{3} }{2}$

⇒ $\frac{AB}{<klux>15</klux>}=\sqrt{3}$

⇒ AB = 1.732 × 15

= 25.98 m.

∴ The height of the kite from the ground is 25.98 m.

Refer to the attachment for the figure and explanation.