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A person hears the sound of the explosion of a bomb after 5 s and another person hears the sound after 6 s. The ratio of minimum and maximum possible distance between the person is _____. ( velocity of sound in air is `330 ms^(-1)`)A. `1 : 1`B. `1 : 2`C. `1 : 11`D. `5 : 6` |
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Answer» Correct Answer - C Speed of Sound `= ("distance between the bomb and the person")/("Time interval")` Minimum distance between them is equal to the distance travelled by the sound in `6 - 5 = 1 s` `d_(1) = s xx t = 330 xx 1 = 330 ` The maximum distance between them is equal to the distance travelled by the sound in `6 + 5 = 11 s` `d_(2) = v xx t = 330 xx 11` `d_(1) : d_(2) = d_(1)/d_(2) = (330 xx 1)/(330 xx 11) = 1/11 = 1 : 11` |
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