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A person can throw a stone to a maximum distance of h meter. The greatest height to which he can throw the stone is:A. `h`B. `h//2`C. `2h`D. `3h` |
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Answer» Correct Answer - b `R=(u^(2) sin 2theta)/g` When `2 theta=90^(@) then R=R_(max)=(u^(2))/g` Given `R_(max)=h, hence (u^(2))/g=h` Height H is given by : `H=(u^(2) sin^(2) theta)/(2g)` When `theta=90^(@), H=H_(max)=(u^(2))/(2g)=h/2` |
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