A pendulum oscillate 60 times 3 second. Find its Time period and frequ

1.	A pendulum oscillate 60 times 3 second. Find its Time period and frequency.
Answer» $\huge\mathbb{SOLUTION:-}$ $\sf\bullet Number\:of\: oscillation= 60\\ \\ \sf\bullet <klux>TIME</klux>\:taken=3sec$ So, $\boxed{\sf{\star{Time\:Period=\dfrac{Time\:taken}{Number\:of\: oscillations}}}}$ $\underline{\sf{\blue{<klux>FREQUENCY</klux>=\dfrac{1}{T}}}}$ or $\boxed{\sf{\bigstar{Frequency=\dfrac{No.\:of\: oscillation}{Time\:taken}}}}$ FIRST FIND the Time period $\sf\implies Time\: Period=\dfrac{\cancel3}{\cancel{15}}\\ \\ \sf\implies Time\: Period=\dfrac{1}{5}\\ \\ \sf\implies Time\: period=0.2second$ Now find the Frequency $\sf\implies Frequency=\dfrac{No.\:of\: oscillation}{Time\:taken}\\ \\ \sf\implies frequency=\dfrac{60}{3}\\ \\ \sf\implies frequency=\cancel{\dfrac{60}{3}}\\ \\ \sf\implies frequency=20Hz$ $\boxed{\sf{\dag{Time\: period=0.2sec}}}$ $\boxed{\sf{\dag{frequency=20Hz}}}$

A pendulum oscillate 60 times 3 second. Find its Time period and frequency.

Answer»

$\huge\mathbb{SOLUTION:-}$

$\sf\bullet Number\:of\: oscillation= 60\\ \\ \sf\bullet <klux>TIME</klux>\:taken=3sec$

$\boxed{\sf{\star{Time\:Period=\dfrac{Time\:taken}{Number\:of\: oscillations}}}}$

$\underline{\sf{\blue{<klux>FREQUENCY</klux>=\dfrac{1}{T}}}}$

$\boxed{\sf{\bigstar{Frequency=\dfrac{No.\:of\: oscillation}{Time\:taken}}}}$

FIRST FIND the Time period

$\sf\implies Time\: Period=\dfrac{\cancel3}{\cancel{15}}\\ \\ \sf\implies Time\: Period=\dfrac{1}{5}\\ \\ \sf\implies Time\: period=0.2second$

Now find the Frequency

$\sf\implies Frequency=\dfrac{No.\:of\: oscillation}{Time\:taken}\\ \\ \sf\implies frequency=\dfrac{60}{3}\\ \\ \sf\implies frequency=\cancel{\dfrac{60}{3}}\\ \\ \sf\implies frequency=20Hz$

$\boxed{\sf{\dag{Time\: period=0.2sec}}}$

$\boxed{\sf{\dag{frequency=20Hz}}}$

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