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a pendulum of length 2.5 metre is made to oscillate at place where G is 10 second square and calculate the time period of the pendulum​

Answer» TION:time PERIOD of PENDULUM is GIVEN by T= 2pi√(l/g)SINCE l=2.5 mg=10m/sec^2pi =3.14then T= 2*3.14√(2.5/10) T=2*3.14*0.5 T=3.14secplease mark as Braineliast


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