1.

A pendulum has a frequency of 5 vibrations per second. An observer starts the pendulum and fires a gun simultaneously. He hears echo from the cliff after 8 vibrations of the pendulum. If the velocity of sound in air is 340 m s-1, find the distance between the cliff and the observer.

Answer»

5 vibrations by pendulum in 1 sec

So 8 vibrations in 8/5 seconds = 1.6 sec

Velocity = 2 × D/ time

340 = 2 × D/ 1.6

D = 340 × 1.6 / 2 = 272 m



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