A pendulum Bob of mass m is held in horizontal position and then released show that the velocity of Bob at lowest position is under root of 2gl

A pendulum Bob of mass m is held in horizontal position and then relea

1.	A pendulum Bob of mass m is held in horizontal position and then released show that the velocity of Bob at lowest position is under root of 2gl
Answer» -------------------0. U = MGL KE=0 \| \| \| \| \| 0 KE = 1/2 mv² U= 0 since only conservative FORCE is ACTING on bob sum of initial energy is conserved => mgl = 1/2 mv² => V =√(2gl)

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A pendulum Bob of mass m is held in horizontal position and then released show that the velocity of Bob at lowest position is under root of 2gl

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