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a peeble is thrown vertically upwards and rises to a height of 19.6m find the time taken by the ball to reach max height |
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Answer» 6 m. U = ? V = 0s = ut +1/2 gt^2 (let g = 10m/s)19.6 = ut + 5t^2 ---- 1V = u + gt0 = u + 10t --- 2Substituting VALUE of u in equation 2, we getu = -10tSubstituting value of u in equation 1, we get,19.6 = -10t^2 + 5t^2- 5t^2 = 19.6t^2 = - 3.92 (Squares cannot be negative. HENCE TAKE mod value)t = √3.92 = 1.97 seconds or 2 seconds. corrections in your question :-u is not given. the values cannot be negative. Please repost the question again with a better question FRAMEWORK. |
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