A peacock is siting on a pillar 9 m high. A snake at a distance of 27

1.	A peacock is siting on a pillar 9 m high. A snake at a distance of 27 m from the pilming to a hole at the base of the pillar. Seeing the snake, the peacock pounces uIf their speeds are equal, then find at what distance from the hole is snake caught
Answer» Let AB be the pillar of height 9 meter. The peacock is sitting at point A on the pillar and B is the foot of the pillar. (.. AB = 9)Let C be the position of the snake which is at 27 meters from B. (.. BC = 27 and ABC = 90) As the speed of the snake and of the peacock is same they will travel the same distance in the same time...Now take a point D on BC that is equidistant from A and C. (Please note that snake is moving towards the pillar and hence B-D-C)Hence by condition 1 AD = DC = y (say)Take BD = x Now consider triangle ABD which is a right angled triangleUsing Pythagorus theorem (AB + BD = AD).. 9 + x = y9 = y - x = (y-x)(y+x)81/(y+x) = (y-x)y+x = BC = 27Hence 81/27 = (y-x) = 3y - x = 3y + x = 27Adding gives 2y = 30 or y = 15x = 27 - y = 12 Thus the snake is caught at a distance of x meters or 12 meters from the hole.

A peacock is siting on a pillar 9 m high. A snake at a distance of 27 m from the pilming to a hole at the base of the pillar. Seeing the snake, the peacock pounces uIf their speeds are equal, then find at what distance from the hole is snake caught

Answer»

Let AB be the pillar of height 9 meter. The peacock is sitting at point A on the pillar and B is the foot of the pillar. (.. AB = 9)Let C be the position of the snake which is at 27 meters from B. (.. BC = 27 and ABC = 90)

As the speed of the snake and of the peacock is same they will travel the same distance in the same time...Now take a point D on BC that is equidistant from A and C. (Please note that snake is moving towards the pillar and hence B-D-C)Hence by condition 1 AD = DC = y (say)Take BD = x

Now consider triangle ABD which is a right angled triangleUsing Pythagorus theorem (AB + BD = AD).. 9 + x = y9 = y - x = (y-x)(y+x)81/(y+x) = (y-x)y+x = BC = 27Hence 81/27 = (y-x) = 3y - x = 3y + x = 27Adding gives 2y = 30 or y = 15x = 27 - y = 12

Thus the snake is caught at a distance of x meters or 12 meters from the hole.

A peacock is siting on a pillar 9 m high. A snake at a distance of 27 m from the pilming to a hole at the base of the pillar. Seeing the snake, the peacock pounces uIf their speeds are equal, then find at what distance from the hole is snake caught

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