a passenger train of length 60m travels at a speed of 80km/h . Another freight train of length 120m travels at a speed of 30 km/h .The ratio of times taken by the passenger train to completely cross the freight train when they are moving in the small direction,and in the opposite direction is

a passenger train of length 60m travels at a speed of 80km/h . Another

1.	a passenger train of length 60m travels at a speed of 80km/h . Another freight train of length 120m travels at a speed of 30 km/h .The ratio of times taken by the passenger train to completely cross the freight train when they are moving in the small direction,and in the opposite direction is
Answer» t₁ : t₂ :: 11 : 5Explanation:Distance to be COVERED = (Total length of freight TRAIN) + (It's own length too) = 120 + 60 m = 180 meterWhen they are GOING in same direction:Relative velocity of passenger train = 80 - 30 = 50 km/hWhen they are going in opposite direction:Relative velocity of passenger train = 80 + 30 = 110 km/hSince,Hence, Ratio of time taken in first and second condition:

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a passenger train of length 60m travels at a speed of 80km/h . Another freight train of length 120m travels at a speed of 30 km/h .The ratio of times taken by the passenger train to completely cross the freight train when they are moving in the small direction,and in the opposite direction is​

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a passenger train of length 60m travels at a speed of 80km/h . Another freight train of length 120m travels at a speed of 30 km/h .The ratio of times taken by the passenger train to completely cross the freight train when they are moving in the small direction,and in the opposite direction is