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A particle whose speed is `50ms^(-1)` moves along the line from `A(2,1)` to `B(9,25)`. Find its velocity vector in the from of `ahat(i)+bhat(j)`. |
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Answer» Correct Answer - 25 `vec(V)=50.vec(AB) vec(AB)=(9-2)hat(i)+(25-1)hat(j)` `50/25(7hat(i)+24hat(j)) |vec(AB)|=sqrt((7)^(2)+(24)^(2))=14hat(i)+48hat(j)=25` |
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