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A particle starts to move in a straight line from a point with velocity 10 M per second and acceleration - 2 metre per second square find the position and velocity of the particle at.....t=5sec...t=70sec |
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Answer» when t=5 x=35m when t=70 x=5600m Explanation: x=v1*t+1/2at^2 v1=10m/s a=2m/s^2 when t=5 x=10*5+1/2*2*25 x=35m when t=70 x=10*70+1/2*2*4900 x=5600m |
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