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A particle starts sliding down a friction less inclined plane. if Sn is distance travelled by it from time t=n-1 sec to n sec then find the ratio Sn/Sn+1. .... plz explain..... |
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Answer» equations of MOTION: s = ut + 1/2 a t^2let Ф be the angle of the inclined plane with the horizontal.Acceleration ALONG the inclined plane = g sin ФLet initial velocity at t = 0 SEC, be u = 0 m/s. distance travelled up to n-1 sec: D(n-1) = 1/2 g SinФ * (n-1)² distance travelled up to n sec. : D(n) = 1/2 * g Sin Ф * n² Distance travelled upto n+1 sec: D(n+1) = 1/2 * g Sin Ф * (n+1)² Sn = Distance travelled from t = n -1 sec. to n sec. = 1/2 g Sin Ф * [n² - (n-1)²] = 1/2 g Sin Ф * (2N - 1)Sn+1 = distance travelled from t = n sec to n+1 sec = 1/2 g Sin Ф * (2n +1)RATIO : Sn / Sn+1 = (2n -1) / (2n +1) = 1 - 1 / (n +1/2) |
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