Saved Bookmarks
| 1. |
A particle starts moving in a straight line under an acceleration varying linearly with time. Its velocity time graph is as shown in figure. Its velocity is maximum at t = 3 sec. The time (in sec) when the particle stops is `(tan 37^(@) = 3//4)` |
|
Answer» Correct Answer - 7 a = C - Kt At t = 0, `a = tan 37^(@)` `(3)/(4) = C` at `t = 3, a = 0` `0=(3)/(4)-Kxx3 implies K=(1)/(4)` `a=(3)/(4)-(1)/(4)t` Particle stops, when a = `-tan45^(@)=-1` `-1=(3)/(4)-(1)/(4)` `(t)/(4)=(7)/(4)implies t=7sec` |
|