a particle starts moving from rest state along a straight line under the action of a constant force and travels distance x in the first five seconds. The distance traveled by it in the next five seconds is

a particle starts moving from rest state along a straight line under t

1.	a particle starts moving from rest state along a straight line under the action of a constant force and travels distance x in the first five seconds. The distance traveled by it in the next five seconds is
Answer» Given u=0m/S then $using \: second \: eq \: of \: motion \\ s =ut + \frac{1}{2}a {t}^{2} \\ u = 0 \\ x = \frac{1}{2} \times a \times <klux>5</klux> \times 5 \\ 12.5a = x \\ for \: 10sec \: from \: start \\ let \: <klux>DISTANCE</klux> \: be \: y \: in \: 10sec \\ then \\ y = \frac{1}{2} \times a \times 10 \times 10 = 50a \\ \frac{x}{y} = \frac{12.5a}{50a} \\ 4x = y$ hence distance TRAVELLED in next 5 sec = Total distance in 10sec-total distance in first FIVE second 4x-x=3X hence 3x is distance travelled

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a particle starts moving from rest state along a straight line under the action of a constant force and travels distance x in the first five seconds. The distance traveled by it in the next five seconds is

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