1.

A particle starts from rest and accelerates at constant rate of 5m/s2 fin the distance travelled in 4 seconds

Answer» ACCORDING to the EQUATIONS of motion
s = ut +  \frac{1}{2} a {t}^{2}
s = 0 \times 4 +  \frac{1}{2}  \times 5 \times  {4}^{2}
s = 40
So distance=40m


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