A particle performing uniform circular motion in a circle of radius is 2m if its frequency of revolution 60 r.p.m find the period of revolution, linear speed, centripetal acceleration of a particle

A particle performing uniform circular motion in a circle of radius is

1.	A particle performing uniform circular motion in a circle of radius is 2m if its frequency of revolution 60 r.p.m find the period of revolution, linear speed, centripetal acceleration of a particle
Answer» he FREQUENCY of revolution of the particle is 60r.p.m., i.e., (60÷60)=1 r.p.s.So, n=1.Time period will be the angular velocity will be so, w=2×π×1or, w=2πThus, the linear speed will be v=w×ror, v=2π×2=4π m/sThe centripetal ACCELERATION will be equal to where, by REPLACING the values of m,w,r, one can DEDUCE the value of the centripetal acceleration.So, centripetal acceleration will be 8m(π^2) m/squ. sec

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A particle performing uniform circular motion in a circle of radius is 2m if its frequency of revolution 60 r.p.m find the period of revolution, linear speed, centripetal acceleration of a particle

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