A particle of unit mass undergoes one-dimensional motion such that its velocity varies according to v(x)=βx−2n.Where, β and n are constants and x is the position of the particle. Find The acceleration of the particle as a function of x, if n=2

A particle of unit mass undergoes one-dimensional motion such that its

1.	A particle of unit mass undergoes one-dimensional motion such that its velocity varies according to v(x)=βx−2n.Where, β and n are constants and x is the position of the particle. Find The acceleration of the particle as a function of x, if n=2
Answer» A particle of unit mass undergoes one-dimensional motion such that its velocity varies according to $v (x) = β x^{- 2 n}$ .Where, $β$ and $n$ are constants and $x$ is the position of the particle. Find The acceleration of the particle as a function of $x$ , if $n = 2$

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A particle of unit mass undergoes one-dimensional motion such that its velocity varies according to v(x)=βx−2n.Where, β and n are constants and x is the position of the particle. Find The acceleration of the particle as a function of x, if n=2

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