1.

A particle of mass m moving with velocity v is collide with a stationary particle of mass 2 m . The speed of the system , after collision will be ……….

Answer»

`v/2`
2v
`v/3`
3v

Solution :
Here `m_(1)=m, v_(1) =v`
`m_(2) =2M, v_(2) =0`
Suppose after collision speed of the system = v
Momentum is CONSERVED in collision of both PARTICLES .
` :. M_(1)v_(1)+m_(2)v_(2) =(m_(1)+m_(2))v`
` :. v. = (MV+2mxx0)/(m+2m)`
` :.v = (mv)/(3m)`
` :. v = v/3`


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