A particle of mass m moves along the quarter section of the circular p

1.	A particle of mass m moves along the quarter section of the circular path whose center is the origin. The radius of the circular path is a. A force F=¯F=y^i−x^j N acts on the particle where x and y denote the coordinates of the position of the particle. The work done by this force in taking the particle from point A (a, 0) to point B (0, a) along the circular path is
Answer» A particle of mass m moves along the quarter section of the circular path whose center is the origin. The radius of the circular path is a. A force $F = ¯ F = y^i - x^j N$ acts on the particle where x and y denote the coordinates of the position of the particle. The work done by this force in taking the particle from point A (a, 0) to point B (0, a) along the circular path is

A particle of mass m moves along the quarter section of the circular path whose center is the origin. The radius of the circular path is a. A force F=¯F=y^i−x^j N acts on the particle where x and y denote the coordinates of the position of the particle. The work done by this force in taking the particle from point A (a, 0) to point B (0, a) along the circular path is

Answer»

A particle of mass m moves along the quarter section of the circular path whose center is the origin. The radius of the circular path is a. A force $F = ¯ F = y^i - x^j N$ acts on the particle where x and y denote the coordinates of the position of the particle. The work done by this force in taking the particle from point A (a, 0) to point B (0, a) along the circular path is

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