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| 1. |
A particle of mass m is projected with speed u at an angle theta with the horizontal. Find the torque of the weight of the particle about the point of projection when the particle is at the highest point. |
| Answer» Solution :`tau =rF = R XX mg = (v_(0)^(2) sin 2theta//2g) xx mg = mv_(0)^(2) sin theta//2` | |