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. A particle of mass M is fired with speed u makingangle θ with the horizontal. Its potential energy atthe highest point is- |
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Answer» Final potential energy = MgH where H is maximum height of projectile. H = u^2 sin^2 theta/2g So, Final potential energyPEf = -Mgu^2 sin^2 theta/2g = - Mu^2 sin^2 theta/2 |
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