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A particle of mass m has an electric charge q. This particle is accelerated through a potential difference V and then entered normally in a uniform magnetic field B. It performs a circular motion of radius R. The ratio of its charge to the mass (q/m) is = ______ [(q/m) is also called specific charge.] (A) 2V/B²R² (B) V/2BR (C) VB/2R (D) mV/BR |
| Answer» IO of its charge to the mass (q/m) is Given:Mass of the particle = mCharge of the particle = qVelocity of the particle = vPotential DIFFERENCE = VMagnetic field = BRadius of the motion = R To find:Ratio of charge to the mass = ?Solution:From question, the particle is electron which is accelerated through potential difference.By energy conversion:SINCE, the particle ENTERS MAGNETIC field, magnetic field is:The velocity of the electron is given by the formula:On squaring on both sides, | |