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A particle of mass m and charge Q is placed in an electric field E which varies with time t as E = E0 sin ωt. It will undergo simple harmonic motion of amplitude(a) QE02/mω2(b) QE0/mω2(c) √(QE0/mω2)(d) QE0/mω |
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Answer» Correct Answer is: (b) QE0/mω2 For a particle undergoing SHM with an amplitude A and angular frequency ω, the maximum acceleration = ω2A. Here, the maximum force on the particle = QE0. ∴ its maximum acceleration = QE0/m = ω2A or A = QE0/mω2. |
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