1.

A particle of mass `2kg` starts to move at position `x=0` and time `t=0` under the action of force `F=(10+4x)N` along the `x- ` axis on a frictionless horizontal track . Find the power delivered by the force in watts at the instant the particle has moved by distance `5m`.

Answer» Correct Answer - 300
According to `W.E.` theorem
`(1)/(2)mV^(2)-0=underset(0)overset(5)int(10+4x)dx`
`V=10m//s`
Force at that moment `=(10+20)=30N`
Instataneous power `= vec(F).vec(V)`
`=30xx10=300W`


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