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A particle of mass `2kg` starts to move at position `x=0` and time `t=0` under the action of force `F=(10+4x)N` along the `x- ` axis on a frictionless horizontal track . Find the power delivered by the force in watts at the instant the particle has moved by distance `5m`. |
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Answer» Correct Answer - 300 According to `W.E.` theorem `(1)/(2)mV^(2)-0=underset(0)overset(5)int(10+4x)dx` `V=10m//s` Force at that moment `=(10+20)=30N` Instataneous power `= vec(F).vec(V)` `=30xx10=300W` |
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