1.

A particle of mass 10gm is describing an SHM along a straight line with a time period of 2sec and amplitude 10cm. Then its KE at 2 cm from the equilibrium position is

Answer»

`4.8 xx 10^(-4)J`
`9.6 xx 10^(-4)J`
`4.8 xx 10^(3) J`
`9.6 xx 10^(3)J`

Answer :A


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