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A particle of mass 10 g moves along a circle of radius 6.4 cm with a constant |
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Answer» cle of mass 10 g moves along a circle of RADIUS 6.4 cm with a constant tangential acceleration. What is the MAGNITUDE of this acceleration if the kinetic energy of the particle becomes equal to 8 X 10^-4 J by the end of the second revolution after the beginning of the MOTION?kinetic energy = 8 × 10^-4 Jor, 1/2 mv² = 8 × 10^-4 or, 1/2 × 10 × 10^-3 v² = 8 × 10^-4 or, v² = 16 × 10^-2 => V = 0.4 m/s initial velocity of particle, u = 0 m/s we have to find Tangential acceleration at the end of 2nd revolution. total distance covered, s = 2(2πr) = 4πr so, v² = 2as a = v²/2s = (0.4)²/2(4πr) = 16 × 10^-2/(8 × 3.14 × 6.4 × 10^-2) = 0.0995 m/s² ≈ 0.1 m/s² |
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