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A particle of mass `1.5` kg moves along x-axis in a conservative force field. Its potential energy is given by `V(x)=2x^(3)-9x^(2)+12x,` where all quantities are written in SI units. The plot of this potential energy is given below. It is seen that the particle can be in stable equilibrium at a point on x-axis, x_(0). When it is displaced slightly from this equilibrium position, It executes SHM with time period T. What is the time period of SHM mentioned in the paragraph?A. `pi sec`B. `2pi sec`C. `pi/2 sec`D. `pi/4 sec` |
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Answer» Correct Answer - A `a=F=-6(x^(2)-3x+2)` `a=-4(x^(2)-3x+2)=-4((2+y)^(2)-3(2+y)+2)` `=-4(4+y^(2)+4y-6-3y+2)` `a=-4y` `omega-2` `T=(2pi)/2=pi sec` |
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