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A particle of mass 0.3 kg is subjected to a force of F = -kx with k= 15 Nmr-1 . What will be its initial acceleration if it is released from a point 20 cm away from the origin? |
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Answer» As F = ma so F = -kx = ma a = \(\frac{-kx}{m}\) for x = 20 cm, ⇒ a = -10 m/s2 |
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