A particle of mass 0.3 kg is subjected to a force of F = -kx with k = 15 Nm^(-1). What will be its initial acceleration if it is released from a point 20 cm away from the origin?

A particle of mass 0.3 kg is subjected to a force of F = -kx with k =

1.	A particle of mass 0.3 kg is subjected to a force of F = -kx with k = 15 Nm^(-1). What will be its initial acceleration if it is released from a point 20 cm away from the origin?
Answer» Solution :F = ma , so F= - KX = ma `a = (-kx)/(m)` For x = 20 cm ` RARR a =-10 m//s^2`