A particle of mass 0.1 kg moving with an initial speed v collides with another particle of same mass kept at rest. If after collision total energy becomes 0.2J, then the minimum and maximum value of 'v' are

A particle of mass 0.1 kg moving with an initial speed v collides with

1.	A particle of mass 0.1 kg moving with an initial speed v collides with another particle of same mass kept at rest. If after collision total energy becomes 0.2J, then the minimum and maximum value of 'v' are
Answer» Solution :In case of PERFECTLY inelastic collision the velocity of combined mass will be `v//2` `therefore KE = (1)/(2) (2M) ((v^(2)),(4))` i.e., `(0.2) = (1)/(2) (0.2) ((v^(2))/(4)) rArr v= 2 sqrt2 m//s` In case of perfectly elastic collision, FIRST particle stops and the SECOND acquires the same velocity v `KE = (1)/(2) mv^(2)` i..e., `0.2 = (1)/(2) (0.1)v^(2)rArr v= 2 m//s` Therfore, MINIMUM value of v is 2m/s in case of perfectly elastic collision and maximum value of v is `2 sqrt2 m//s` in case of perfectly inelastic collision.