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A particle of charge q and mass m starts moving from the origin under the action of an electric field →E=E0^i and →B=B0^i with velocity →v=v0^j. The speed of the particle will become 2v0 after a time |
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Answer» Correct option is D t= qE 3 mv 0
is PARALLEL to B and v is perpendicular to both. THEREFORE, path of the particle is a HELIX with increasing pitch. Speed of particle at any time t is v= v x 2 +v y 2 +v z 2
....(1) Here, v y 2 +v z 2 =v 0 2
And v x 2 =( m qE t) 2
And v=2v 0
SUBSTITUTING the value in eq (1), we get t= qE 3 mv 0
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