1.

A particle of charge q and mass m moves in a circular orbit of radius r with angular speed omega. The ratio of the magnitude of its magnetic moment to that of its angular momentum depends on

Answer»

`omega` and Q
`omega`,q and m
q and m
`omega` and m

Solution :RATIO of magnetic moment and angular momentum is given by `M/L=q/(2M)`
which is a function of q and m only. This can be derived as follows
`M=1A = (qupsilon)(pir^2)=(q)(omega/(2PI))(pir^2)=(qomegar^2)/2`
`L=Iomega=(mr^2omega) THEREFORE M/L=(q omegar^2//2)/(mr^2omega)=q/(2m)`


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