A particle of charge q and mass m is moving with a velocity −v^i(v≠0) towards a large screen placed in the (Y−Z) plane at a distance d. If there is a magnetic field →B=B0^k, the maximum value of v for which the particle will not hit the screen is :

A particle of charge q and mass m is moving with a velocity −v^i(v�

1.	A particle of charge q and mass m is moving with a velocity −v^i(v≠0) towards a large screen placed in the (Y−Z) plane at a distance d. If there is a magnetic field →B=B0^k, the maximum value of v for which the particle will not hit the screen is :
Answer» A particle of charge $q$ and mass $m$ is moving with a velocity $- v^i (v \neq 0)$ towards a large screen placed in the $(Y - Z)$ plane at a distance $d$ . If there is a magnetic field $\to B = B_{0}^k$ , the maximum value of $v$ for which the particle will not hit the screen is :

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A particle of charge q and mass m is moving with a velocity −v^i(v≠0) towards a large screen placed in the (Y−Z) plane at a distance d. If there is a magnetic field →B=B0^k, the maximum value of v for which the particle will not hit the screen is :

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