A particle of charge 3.2×10−19C travels through a potential difference of 10−2 Volts from rest, the final speed of particle is _______ (m=1.6×10−27kg)

A particle of charge 3.2×10−19C travels through a potential differe

1.	A particle of charge 3.2×10−19C travels through a potential difference of 10−2 Volts from rest, the final speed of particle is _______ (m=1.6×10−27kg)
Answer» A particle of charge $3.2 \times 10^{- 19} C$ travels through a potential difference of $10^{- 2}$ Volts from rest, the final speed of particle is _______ $(m = 1.6 \times 10^{- 27} k g)$

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A particle of charge 3.2×10−19C travels through a potential difference of 10−2 Volts from rest, the final speed of particle is _______ (m=1.6×10−27kg)

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