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A particle moving with uniform acceleration along a straight line from rest. The percentage increase in displacement during sixth second compared to that in 5th second is

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centage increase in DISPLACEMENT during sixth second COMPARED to that in 5th second is 44%Explanation : LET the acceleration of the particle is a m/s²From the laws of motion we know that,S = ut + at²/2since u = 0, hence S = at²/2Displacement at the end of 5 second,S₅ = a(5)²/2 = 12.5aDisplacement at the end of 6 second,S₆ = a(6)²/2 = 18aIncrease in displacement,S = 18A - 12.5a = 5.5aHence percentage increase in displacement= (5.5/12.5) x 100= 44%Hence The percentage increase in displacement during sixth second compared to that in 5th second is 44%



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