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A particle moving rectilinearly with constant acceleration is having initial velocity of 10 M per second after sometime velocity becomes 30 metre per second find the velocity of particle at the midpoint of its path |
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Answer» Let the TOTAL distance be 2x Therefore distance up to mid point is equal to X. Let the VELOCITY at midpoint be v And acceleration be a. From equations of motion : v² = 10² + 2ax............... 1) 30² = v² + 2ax.............. 2) (2) - (1) gives : 30² - v² = v² - 10² 900 + 100 = 2v² 1000 = 2v² v² = 1000/2 v² = 500 v = √500 v = 10√5 m/s |
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