1.

A particle moving rectilinearly with constant acceleration is having initial velocity of 10 M per second after sometime velocity becomes 30 metre per second find the velocity of particle at the midpoint of its path

Answer»

Let the TOTAL distance be 2x

Therefore distance up to mid point is equal to X.

Let the VELOCITY at midpoint be v

And acceleration be a.

From equations of motion :

v² = 10² + 2ax............... 1)

30² = v² + 2ax.............. 2)

(2) - (1) gives :

30² - v² = v² - 10²

900 + 100 = 2v²

1000 = 2v²

v² = 1000/2

v² = 500

v = √500

v = 10√5 m/s




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