A particle moves with velocity function v(t) = -t2 + 5t - 3, with v measured in feet per second and t measured in seconds. Find the acceleration of the particle at time t = 3 seconds

A particle moves with velocity function v(t) = -t2 + 5t - 3, with v me

1.	A particle moves with velocity function v(t) = -t2 + 5t - 3, with v measured in feet per second and t measured in seconds. Find the acceleration of the particle at time t = 3 seconds
Answer» given V( t )= -t² +5t -3 differentiate both sides with respect to t d( v) /dt =-2t + 5v or d (v)/dt. when t =3 =-2(3) +5 acceleration. = -1 BCOZ RATE or change of velocity gives acceleration

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A particle moves with velocity function v(t) = -t2 + 5t - 3, with v measured in feet per second and t measured in seconds. Find the acceleration of the particle at time t = 3 seconds

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