1.

A particle moves with a velocity (5hati-3hatj+6hatk) m/s under the influence of a constant force vecF = (10hsti+10hatj+20hatk) N. The instantaneous power applied to the particle is

Answer»

200 W 
40
140
170 W 

Solution :As `vecv = (5 HATI + 6 hatk) m//s, vecF (10 hati + 10 hatj + 20 hatk) N`
`:.` Power = `vecF. Vecv = (10 hati + 10 hatj + 20 hatk). (5 hati - 3hatj + 6hatk)`
`= 50 - 30 + 120 = 140 W`


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