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A particle moves in the XY-plane according to the law `x = kt, y = kt (1- alphat)`, where k and `alpha` are positive constants and t is time. The trajectory of the particle isA. `y = kx`B. `y = x - (alpha x^(2))/(k)`C. `y =- (ax^(2))/(k)`D. `y = alpha x` |
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Answer» Correct Answer - B `x = kt, t = (x)/(k)` Now, `y = k ((x)/(k)) (1-alpha.(x)/(k))` or `y = x - (alpha x^(2))/(k)` |
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