A particle moves in the x−y plane under the influence of a force such that its linear momentum is →p(t)=A[cos(kt)^i−sin(kt)^j], where A and k are constants. The angle between the force and the momentum is :

A particle moves in the x−y plane under the influence of a force suc

1.	A particle moves in the x−y plane under the influence of a force such that its linear momentum is →p(t)=A[cos(kt)^i−sin(kt)^j], where A and k are constants. The angle between the force and the momentum is :
Answer» A particle moves in the $x - y$ plane under the influence of a force such that its linear momentum is $\to p (t) = A [cos (k t)^i - sin (k t)^j]$ , where $A$ and $k$ are constants. The angle between the force and the momentum is :

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A particle moves in the x−y plane under the influence of a force such that its linear momentum is →p(t)=A[cos(kt)^i−sin(kt)^j], where A and k are constants. The angle between the force and the momentum is :

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