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A particle moves in the X-Y plane under the action of a force vec(F) such that the value of its linear momentum (vec(P)) at any time .t., and its components are P_(X) = 2 cos t, P_(Y) = 2 sin t. According to defination of force vec(F) = (d vec(P))/(dt) The angle .theta. between vec(F) and vec(P) at a given time .t. will be |
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Answer» `THETA = 0^(@)` |
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