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A particle moves along x-axis from x=0 "to"x=8 under the influence of a force given by F=3x^(2)-4x+5. Find thework done in the process. |
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Answer» Solution :WORK donein the moving a PARTICLE from x=0 to x=8 wil be `W=underset(0)overset(8)INT(3x^(2)-4x+5)dx=[(3x^(3))/3-(4x_(2))/2+5x]_(0)^(8)` `W=[3""(8)^(3)/3-4".(8^(2)/2)+40]=[512-128+40]=424J` |
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