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A particle moves along the curve `x^(2)=2y`. At what point, ordinate increases at the same rate as abscissa increases ? |
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Answer» `x^2y......(1)` `rArr2x(dx)/(dt)=2(dy)/(dt)" "("given "(dy)/(dt)=(dx)/(dt))` `rArr 2x(dx)/(dt)=2(dx)/(dt)` `rArr x=1` from (1) `y=(1)/(2)` so point is `(1,(1)/(2))` |
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