1.

A particle moves along a straight line such that itsdisplacements at any time t is given by 87-6f+37+4metres. The velocity, when the acceleration is zero, is:

Answer»

2 sec

Correct answer

Given,s = t^3 - 6t^2 + 3t + 4

Then,Velocity is ds/dtv = 3t^2 - 12t + 3

Acceleration is dv/dta = 6t - 12

If acceleration is 06t - 12 = 06t = 12t = 12/6 = 2

Therefore,Velocity = 3*(2)^2 - 12*2 + 3= 3*4 - 24 + 3= - 12 + 3 = - 9 m/sec



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